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C语言简易版小游戏【flappy bird】
栏目分类:源码分享发布日期:2020-01-27浏览次数:

C语言简易版小游戏【flappy bird】 #include stdio.h #include stdlib.h #includeconio.h #include interface.h char interf[M][N] = {{ 32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35 },

C语言简易版小游戏【flappy bird】

#include <stdio.h>
#include <stdlib.h>
#include<conio.h>
#include "interface.h"
 
 
char interf[M][N] = {{ 32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35 },
                    { 32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35 },
                    { 32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35 },
                    { 32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35 },
                    { 32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35 },
                    { 32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35 },
                    { 32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35 },
                    { 32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35 },
                    { 32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,32,32 },
                    { 32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,32,32 },
                    { 38,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32 },
                    { 32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32 },
                    { 32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,35,35 },
                    { 32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,35,35 },
                    { 32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35 },
                    { 32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35 },
                    { 32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35 },
                    { 32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35 },
                    { 32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35 },
                    { 32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35,32,32,32,32,32,32,32,32,32,32,35,35 }, };
//初始界面矩阵,ASCII码中“ ”是32,“&”是38表示小鸟,“#”是35用来画柱子
 
int num = 0;//用于计数输出并排两列黑柱子同一位置
int black;//黑方块位置
int p= M/2 ;//小鸟初始位置
int score = 0;//分数
 
/*初始化界面*/
void InitialInterface(void)
{
        printf("\n          作者:xhyang,博客地址:http://blog.csdn.net/weixin_39449570\n");
        printf("            按\"w\"使小鸟跳起来,别落地,顺利穿过尽可能多的柱子!\n");
        for (int i = 0; i < M; i++)
        {
            printf("            ");
            for (int j = 0; j < N; j++)
            {
                printf("%c", interf[i][j]);
            }
            printf("\n");
        }
}
 
 
/*更新界面各个柱子*/
void newinterface(void)
{
 
    if (interf[0][1] == 35 && num==0)//当矩阵第二列为黑色方块时,计算出下一次黑柱子上半部分的位置
    { 
        black = 5 + rand() % 5;
        num = 2;//黑柱子是两列#组成,第二列与第一列位置一样,用num保证两列位置一致
    }
    for (int i = 0; i < M; i++)
    {
 
        for (int j = 0; j < N - 1; j++)
        {
            interf[i][j] = interf[i][j + 1];
        }
        if (interf[0][0] == 35 && (i < black || i>(black + 5)))//此时上面的第二列变成了第一列,更新下一个黑柱子,有了黑柱子上半部分位置+5即是下半部分的起始位置
        {
            interf[i][N-1] = 35;
        }
        else
        {
            interf[i][N-1] = 32;
        }
    }
    if (num > 0)
        num--;
}
 
 
/*更新小鸟位置*/
void birdmove(void)
{
    for (int a = 0; a < 3; a++)
    {
        if (a  == 2 && p > 0)//减缓鸟的速度,使按键上跳速度是下落的4倍
        {
            p = p + 1;
        }
        if (_kbhit())
        {
            if (_getch() == 'w' || _getch() == 'W')
            {
                p = p - 3;
            }
        }
    }
}
 
/*计分*/
void scoring(void)
{
    if (p > 20 || interf[p][0] == 35)
    {
        system("cls");
        printf("\n\n            游戏结束!\n\n");
        printf("            最终得分:%d\n\n\n", score);
        system("pause");
    }
 
    if (interf[0][0] == 35 && interf[0][1] == 32 )
        score++;
}
 
/*重画界面*/
void draw(void)
{
    system("cls");
    printf("\n          作者:xhyang,博客地址:http://blog.csdn.net/weixin_39449570\n");
    printf("            按\"w\"使小鸟跳起来,别落地,顺利穿过尽可能多的柱子!\n");
    for (int i = 0; i < M; i++)
    {
        printf("            ");
        for (int j = 0; j < N; j++)
        {
            if (i == p && j == 0 && interf[p][0] != 35)
                printf("%c", 38);
            else
                printf("%c", interf[i][j]);
        }
        printf("\n");
 
    }
    printf("            得分:%d \n", score);
}


 

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